As found in Exercise 39, the centroid of the semicircle y = a 2 - x 2
Question:
As found in Exercise 39, the centroid of the semicircle y = √a2 - x2 lies at the point (0, 2a/π). Find the area of the surface swept out by revolving the semicircle about the line y = a.
Data from in Exercise 39
Use Pappus’s Theorem for surface area and the fact that the surface area of a sphere of radius a is 4πa2 to find the centroid of the semicircle y = √a2 - x2.
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To find the centroid of the semicircle y a2 x2 we can use Pappuss Theorem for surface area which sta...View the full answer
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Related Book For
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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