Question: Evaluate the integral. 3 x3 2 + 6 4 dx (x + 1)(x + 2)

Evaluate the integral.Зх3 Зx3 — х2 + 6х — 4 dx (x² + 1)(x² + 2)

3 x3 2 + 6 4 dx (x + 1)(x + 2)

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3xx 6x4 x 1x 2 Equating the coefficients gives A C 3 ... View full answer

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