Question: Evaluate the surface integral. S y dS, S is the surface z = 2/3 (x 3/2 + y 3/2 ), 0 < x <

Evaluate the surface integral.

ʃʃS y dS,
S is the surface z = 2/3 (x3/2 + y3/2), 0 < x < 1, 0 < y < 1

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