Evaluate the surface integral. S z 2 dS, S is the part of the paraboloid x
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Evaluate the surface integral.
ʃʃS z2 dS,
S is the part of the paraboloid x = y2 + z2 given by 0 < x < 1
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Using y and z as parameters we have ry z y ziyjzk y z 1 Then ...View the full answer
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