Question: Find the value of ( g) at the given value of x. f(u) = u + 1 cos u u = g(x) = TTX,

Find the value of (ƒ ∘ g)′ at the given value of x.f(u) = u + 1 cos u u = g(x) = TTX,

f(u) = u + 1 cos u u = g(x) = TTX, x = 1/4

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