Question: If sin = 1/3, in quadrant II, find the exact value of: (a) cose (b) sin(0 + 7) 6 cos (0 - )
If sin θ = 1/3, θ in quadrant II, find the exact value of:
(a) cose (b) sin(0 + 7) 6 cos (0 - ) 3 (c) cos (d) tan (0+1) 4
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Given that sin 13 and is in quadrant II we can find the exact values of the trigonometric functions ... View full answer
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