Question: In Exercises 1924, evaluate S f(x, y, z) dS. f(x, y, z)=x + y + z S: z = x + y, (x

In Exercises 19–24, evaluate ∫S∫ f(x, y, z) dS.


f(x, y, z)=x + y + z S: z = x +

f(x, y, z)=x + y + z S: z = x + y, (x - 1) + y 1

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To evaluate the surface integral S fx y z dS where fx y z x2 y2 z2 and S is the surface defined by z ... View full answer

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