Question: Let f be a twice-differentiable real-valued function satisfying f (x) + f''(x) = -xg(x)f'(x), where g(x) 0 for all real x. Prove that |f

Let f be a twice-differentiable real-valued function satisfying f (x) + f''(x) = -xg(x)f'(x), where g(x) ≥ 0 for all real x. Prove that |f (x)| is bounded.

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