Question: Let f (x) = 2 - |2x - 1|. Show that there is no value of c such that f (3) - f (0) =

Let f (x) = 2 - |2x - 1|. Show that there is no value of c such that f (3) - f (0) = f' (c)(3 - 0). Why does this not contradict the Mean Value Theorem?

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