Refer to the figure. If OA = 1, show that: (a) Area AOAC [(b) Area AOCB =
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Refer to the figure. If OA = 1, show that:
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(a) Area AOAC [(b) Area AOCB = = |OB|² sin ßcos ß (c) Area AOAB = |OB| sin(a + 3) (d) |OB| (e) cosa cos ß sin a cosa sin(a + 3) = sinacos/ß + cosa sin 3 0 R 1 B D A
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a In right angled triangle OAC hyp OA 1 AOC OAC 90 AC OA cos 90 1 sin sin 1 OC OA cos cos 2 Area of ...View the full answer
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Related Book For
Precalculus Concepts Through Functions A Unit Circle Approach To Trigonometry
ISBN: 9780137945139
5th Edition
Authors: Michael Sullivan
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