Question: Show that each function is a solution of the given initial value problem. Differential equation xy' + y = -sin x, x > 0 Initial

Show that each function is a solution of the given initial value problem.Differential equation xy' + y = -sin x, x > 0 Initial

Differential equation xy' + y = -sin x, x > 0 Initial equation y TT 2 = 0 Solution candidate y = COS X X

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