Question: Solve the initial value problems for x as a function of t. dx (t+1) = dt x + 1 (t-1), x(0) = 0

Solve the initial value problems for x as a function of t.dx (t+1) = dt x + 1 (t-1), x(0) = 0

dx (t+1) = dt x + 1 (t-1), x(0) = 0

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ANSWER We have the differential equation t 1 ddtx x2 1 t 1 To solve this differ... View full answer

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