Question: Solve the initial value problems for x as a function of t. (1+2t) dx dt = 2x + 2 (t, x > 0), x(1) =

Solve the initial value problems for x as a function of t.(1+2t) dx dt = 2x + 2 (t, x > 0), x(1)

(1+2t) dx dt = 2x + 2 (t, x > 0), x(1) = 1

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