The equation ax 2 + 2x - 1 = 0, where a is a constant, has two
Question:
The equation ax2 + 2x - 1 = 0, where a is a constant, has two roots if a > -1 and a ≠ 0, one positive and one negative:
a. What happens to r+(a) as a→ 0? As a→ -1+?
b. What happens to r-(a) as a→ 0? As a→ -1+?
c. Support your conclusions by graphing r+(a) and r-(a) as functions of a. Describe what you see.
d. For added support, graph ƒ(x) = ax2 + 2x - 1 simultaneously for a = 1, 0.5, 0.2, 0.1, and 0.05.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
Question Posted: