Question: The function is defined on [0, 1], as shown in the figure. Show that does not exist. Does this contradict Theorem 4.4? Why or why

The function 0, x = 0 f(x) = 1 I >x>0 is defined on [0, 1], as shown in the figure. Show thatdoes not exist. Does this contradict Theorem 4.4? Why or why not?

THEOREM 4.4

0, x = 0 f(x) = 1 I >x>0

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To show that 0 1 fx dx does not exist for the given function we need to demonstrate that the integral diverges or is undefined The function fx is defi... View full answer

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