The position of a projectile fired with an initial velocity v 0 feet per second and at

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The position of a projectile fired with an initial velocity v0 feet per second and at an angle to the horizontal at the end of t seconds is given by the parametric equations 

(vo cos 0)t y = (vo sin 0)t - 1612

See the illustration. 

R•

(a) Obtain the rectangular equation of the trajectory and identify the curve. 

(b) Show that the projectile hits the ground when 

(c) How far has the projectile traveled (horizontally) when it strikes the ground? In other words, find the range R. 

(d) Find the time t when x = y. Then find the horizontal distance x and the vertical distance y traveled by the projectile in this time. Then compute √(x2 + y2). This is the distance R, the range, that the projectile travels up a plane inclined at 45° to the horizontal (x = y).  See the following illustration. 

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Related Book For  answer-question

Precalculus

ISBN: 978-0321716835

9th edition

Authors: Michael Sullivan

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