Question: The position of a projectile fired with an initial velocity v 0 feet per second and at an angle to the horizontal at the end

The position of a projectile fired with an initial velocity v0 feet per second and at an angle to the horizontal at the end of t seconds is given by the parametric equations 

(vo cos 0)t y = (vo sin 0)t - 1612

See the illustration. 

R•

(a) Obtain the rectangular equation of the trajectory and identify the curve. 

(b) Show that the projectile hits the ground when (vo cos 0)t y = (vo sin 0)t - 1612 R

(c) How far has the projectile traveled (horizontally) when it strikes the ground? In other words, find the range R. 

(d) Find the time t when x = y. Then find the horizontal distance x and the vertical distance y traveled by the projectile in this time. Then compute √(x2 + y2). This is the distance R, the range, that the projectile travels up a plane inclined at 45° to the horizontal (x = y).  See the following illustration. 

(vo cos 0)t y = (vo sin 0)t - 1612 R

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