Question: The position of a projectile fired with an initial velocity v 0 feet per second and at an angle to the horizontal at the end
The position of a projectile fired with an initial velocity v0 feet per second and at an angle to the horizontal at the end of t seconds is given by the parametric equations
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See the illustration.
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(a) Obtain the rectangular equation of the trajectory and identify the curve.
(b) Show that the projectile hits the ground when ![]()
(c) How far has the projectile traveled (horizontally) when it strikes the ground? In other words, find the range R.
(d) Find the time t when x = y. Then find the horizontal distance x and the vertical distance y traveled by the projectile in this time. Then compute √(x2 + y2). This is the distance R, the range, that the projectile travels up a plane inclined at 45° to the horizontal (x = y). See the following illustration.
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(vo cos 0)t y = (vo sin 0)t - 1612 R
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a b x v coset y v sint16t tx Vo cos yvo sin e 16106 y tanx X Voc cos ... View full answer
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