A toroidal core has a square cross section, 2.5 cm < < 3.5 cm, 0.5 cm
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A toroidal core has a square cross section, 2.5 cm < ρ < 3.5 cm, −0.5 cm < z < 0.5 cm. The upper half of the toroid, 0 < z < 0.5 cm, is constructed of a linear material for which μr = 10, while the lower half, −0.5 cm < z < 0, has μr = 20. An mmf of 150 A· t establishes a flux in the aϕ direction. For z > 0, find:
(a) Hϕ(ρ);
(b) Bϕ(ρ);
(c) z > 0.
(d) Repeat for z > 0.
(e) Find total.
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a Amperes circuital law gives b We use B r 0 H 10 4 10 7 239 ...View the full answer
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