By substituting (10.60) through (10.62) into (10.59), collecting all like-argument terms in the Q-function, and neglecting squared

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By substituting (10.60) through (10.62) into (10.59), collecting all like-argument terms in the Q-function, and neglecting squared Q-function terms, show that the symbol error probability for 16-QAM reduces to (10.63).

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