Question: Calculate the vector torque on the square loop shown in Figure 8.15 about an origin at A in the field B, given (a) A(0, 0,

Calculate the vector torque on the square loop shown in Figure 8.15 about an origin at A in the field B, given

+2, 2, 0) +2,-2, 0) 0.6 A (2,–2, 0) (2, 2, 0) х


(a) A(0, 0, 0) and B = 100ay mT;

(b) A(0, 0, 0) and B = 200ax + 100ay mT;

(c) A(1, 2, 3) and B = 200ax + 100ay ˆ’ 300az mT;

(d) A(1, 2, 3) and B = 200ax + 100ay ˆ’ 300az mT for x ‰¥ 2 and B = 0 elsewhere.

+2, 2, 0) +2,-2, 0) 0.6 A (2,2, 0) (2, 2, 0)

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a The field is uniform and so does not produce any translation of the loop Therefore we may use T IS ... View full answer

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