Question: If show that (a) E[X 2n ] = 1 · 3 · 5 ··· (2n - 1) Ï 2n , for n = 1,2,... (b)

show that
(a) E[X2n] = 1 · 3 · 5 ··· (2n - 1) Ï2n, for n = 1,2,...
(b) E[X2n-1] = 0 for n = 1,2,...
fx(x) -(2 ') exp 22
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a The integral evaluates as follows where y x 2 12 ... View full answer
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