Let D = 4xya x + 2(x 2 + z 2 )a y + 4yza z nC/m

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Let D = 4xya_x + 2(x² + z²)a_y + 4yza_z nC/m² and evaluate surface integrals to find the total charge enclosed in the rectangular parallelepiped 0 < x < 2, 0 < y < 3, 0 < z < 5 m.

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Engineering Electromagnetics

ISBN: 978-0073380667

8th edition

Authors: William H. Hayt, John A.Buck

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Question Posted: Sep 08, 2018 12:16 PM

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Let D = 4xya x + 2(x 2 + z 2 )a y + 4yza z nC/m

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First consider the planes at y 0 and 3 The y component of D will penetrate those surfaces but will ...View the full answer

Engineering Electromagnetics

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