Question: Let D = 4xya x + 2(x 2 + z 2 )a y + 4yza z nC/m 2 and evaluate surface integrals to find the
Let D = 4xyax + 2(x2 + z2)ay + 4yzaz nC/m2 and evaluate surface integrals to find the total charge enclosed in the rectangular parallelepiped 0 < x < 2, 0 < y < 3, 0 < z < 5 m.
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First consider the planes at y 0 and 3 The y component of D will penetrate those surfaces but will ... View full answer
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