Question: Note that from (10.116) and (10.122) that the 10% out-of-band power RF bandwidth for QPSK is where 1/2T b is the first zero of sinc

Note that from (10.116) and (10.122) that the 10% out-of-band power RF bandwidth for QPSK is В 1об = R, Hz = 2 2T, B10% OOB, QPSK

where 1/2Tis the first zero of sinc (2Tbf). From (10.117) we therefore conclude that for M-ary QAM. 2R, Hz log, M B10% OOB, QAM :2 || (log, M) T,

Consider a channel of 20-kHz bandwidth. What data rate is supported by QAM for:
(a) M = 4;

(b) M = 16; 

(c) M = 64; 

(d) M = 256?

1 = R, Hz = 2 2T, B10% OOB, QPSK 2R, Hz log, M B10% OOB, QAM :2 || (log, M) T,

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