Show that (10.26) and (10.27) are Fourier transform pairs. In 2 (f (10.26) (f) xp 2?
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In 2 (f (10.26) н (f)— еxp 2л? в 2л -B exp In 2 h(t) = (10.27) In 2
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The Fourier transform of h t is H f 2B LBViezexp2ex...View the full answer
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Related Book For
Principles of Communications Systems, Modulation and Noise
ISBN: 978-8126556793
7th edition
Authors: Rodger E. Ziemer, William H. Tranter
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