Question: Given events A, B, C, show that the probability that exactly one of the events occurs equals: P(A) + P(B) + P(C) P(AB)

Given events A, B, C, show that the probability that exactly one of the events occurs equals: 

P(A) + P(B) + P(C) − P(AB) − P(AC) − P(BC) + 3P(ABC).

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