The expected sum of two fair dice is 7, the variance is 35/6. Let X be the
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The expected sum of two fair dice is 7, the variance is 35/6. Let X be the sum after rolling n pairs of dice. Use Chebyshev’s inequality to find z such that P(|X − 7n| < z) ≥ 0.95. In 10,000 rolls of two dice there is at least a 95% chance that the sum will be between what two numbers?
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We have PX 7n z 35n6z 2 Solve 35n6z 2 00...View the full answer
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