Question: Consider the following code skeleton in C++: Explain why the compiler wont allow the second call. Give an example of bad things that could happen

Consider the following code skeleton in C++:

$#include using std::1ist; class foo {... class bar : public foo { ... static void print_all(list &L) { .. list LF; list LB; print_all (LF); print_all (LB); // works fine // static semantic error$

Explain why the compiler won’t allow the second call. Give an example of bad things that could happen if it did.

#include using std::1ist; class foo {... class bar : public foo { ... static void print_all(list &L) { .. list LF; list LB; print_all (LF); print_all (LB); // works fine // static semantic error

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