Question: Repeat Example 2.36 using the grammar of Figure 2.15. Figure 2.15: id(A) id_list_prefix id(C) id_list_prefix id_list_prefix id(B) id(A) id(A) id_list_prefix id_list_prefix id(A) id_list_prefix id(C) id_list_prefix

Repeat Example 2.36 using the grammar of Figure 2.15.

Figure 2.15:

id(A) id_list_prefix id(C) id_list_prefix id_list_prefix id(B) id(A) id(A) id_list_prefix id_list_prefix id(A) id_list_prefix id(C) id_list_prefix id(B) id_list_prefix id(B) id(A) id(A) id_list_prefix id_list_prefix id_list_prefix id(B) id_list_prefix id(C) id_list_prefix id (B) id(A) id_list_prefix id(A) id_list_prefix id(B) id_list id(A) id_list_prefix id_list_prefix id(C) id_list > id_list_prefix ; id_list_prefix id (B) id_list_prefix → id_list_prefix id id(A)

id(A) id_list_prefix id(C) id_list_prefix id_list_prefix id(B) id(A) id(A) id_list_prefix id_list_prefix id(A) id_list_prefix id(C) id_list_prefix id(B) id_list_prefix id(B) id(A) id(A) id_list_prefix id_list_prefix id_list_prefix id(B) id_list_prefix id(C) id_list_prefix id (B) id(A) id_list_prefix id(A) id_list_prefix id(B) id_list id(A) id_list_prefix id_list_prefix id(C) id_list > id_list_prefix ; id_list_prefix id (B) id_list_prefix id_list_prefix id id(A) id

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