Question: Consider the cell S.C.E. i cell solution | Pt(s), whose voltage is 20.126 V. The cell solution contains 2.00 mmol of Fe(NH 4 ) 2
Consider the cell S.C.E. i cell solution | Pt(s), whose voltage is 20.126 V. The cell solution contains 2.00 mmol of Fe(NH4)2(SO4)2, 1.00 mmol of FeCl3, 4.00 mmol of Na2EDTA, and lots of buffer, pH 6.78, in a volume of 1.00 L.
(a) Write a reaction for the right half-cell.
(b) Find the quotient [Fe2+]/[Fe3+] in the cell solution. (This expression gives the ratio of uncomplexed ions.)
(c) Find the quotient of formation constants: (Kf for FeEDTA2)/ (Kf for FeEDTA2-).
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At or below near neutral pH both FeII and FeIII form stable complexes with EDTA So in the solu... View full answer
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