A 40.0-N force stretches a vertical spring 0.250 m.

(a) What mass must be suspended form the spring so that the system will oscillate with a period of 1.0 s?

(b) If the amplitude of the motion is 0.050 m and the period is that specified in part (a) where is the object and in what direction is it moving 0.35 s after it has passed the equilibrium position, moving downward? Take the positive direction to be upward.

(c) What force (magnitude and direction) does the spring exert on the object when it is 0.030 m below the equilibrium position, moving upward?

Answer rating: 100% (QA)

a A 400 N force stretches a spring by 0250 m As F kx in terms of magnitude only Hence 400 k0250 and ... View the full answer