A meter-stick (L = 1 m) has a mass of m = 0.248 kg. Initially it hangs from two short strings: one at the 25 cm mark and one at the 75 cm mark.  

   

1) What is the tension in the left string? -->i found this 1.2152 N 

2) Now the right string is cut! What is the initial angular acceleration of the meter-stick about its pivot point? (You may assume the rod pivots about the left string, and the string remains vertical)

3) What is the tension in the left string right after the right string is cut?

4) After the right string is cut, the meter-stick swings down to where it is vertical for an instant before it swings back up in the other direction. What is the angular speed when the meter-stick is vertical?

5) What is the acceleration of the center of mass of the meter-stick when it is vertical?

6) What is the tension in the string when the meter-stick is vertical?

7) Where is the angular acceleration of the meter-stick a maximum?

Right after the string is cut and the meter-stick is still horizontal

When the meter-stick is vertical – at the bottom of its path

The angular acceleration is constant

Answer rating: 100% (QA)

1 m g2 12152 N 2 Net torque about pivot point m g 025 0... View the full answer