A spring with spring constant k is oriented vertically and compressed downward a distance x from its equilibrium position. An object of mass m is placed on the upper end of the spring, and the spring is released. The object rises a distance h (with h>>x) above the equilibrium position of the spring. If the spring is then compressed downward by the same distance x and an object of mass 3m is placed on it, how high will the object rise when the spring is released?

a) h

b) 3h

c) h/3

d) h3

e) h1/2

Answer rating: 100% (QA)

Expression for elastic potential energy of spring is Ei 12 kr 2 Here E is elastic p... View the full answer