Calculate P ₁ , P ₂ , P ₃ , P _p , Q ₁ , Q ₂ , Power losses in the DCV, Power losses in the FCV, pump real flow rate

The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow valves, as shown in the given circuit.

Given:

Relief valve:

Cracking pressure = 6 MPa

Override pressure = 0

Hydraulic cylinder:

f = 2000 Ns/m

v = 0.1 m/s

F = 9000 N

Piston diameter = 60 mm

Rod diameter = 25 mm

No inner leakage

Transcribed Image Text:

Pump: V = 25 cm³/rev n = 1000 rpm 1, = 0.95 11 = 0.93 n₁ = 1 Directional control valve: Q=6x10-²√AP P₁Q₁ XIIw P₁ (M) Pp M P=0 P₂Q₂ P=0 "↓ Pump: V = 25 cm³/rev n = 1000 rpm 1, = 0.95 11 = 0.93 n₁ = 1 Directional control valve: Q=6x10-²√AP P₁Q₁ XIIw P₁ (M) Pp M P=0 P₂Q₂ P=0 "↓

Answer rating: 100% (QA)

a P 1 FA 9000006 2 4 3183 MPa P 2 FD 1 2 d 2 2 9000006 2 0025 2 4 385 Mpa P 3 6 MPa P p v ... View the full answer