Calculate the volume of CO ₂ that reacts with 1.00 gram of LiOH according to the equation given below. Assume the reaction goes to completion at a pressure of 1.00 atm and temperature of 298K. MW Li = 6.94 g/mol; MW O = 16.0 g/mol; MW H = 1.01 g/mol; MW C = 12.01 g/mol; R = 0.08206 (L*atm)/(mol*K). 2LiOH(s) + CO ₂ (g) → Li ₂ CO ₃ (s) + H ₂ O(g)

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2 LiOH s CO 2 g Li 2 CO 3 s H 2 Og Moles of LiOH Amount taken Molar mass 1 23... View the full answer