Draw the correct structure from the MS, 1H NMR, 13C NMR, and IR data given below. Both of the peaks on the 1H NMR spectrum are doublets (J = 2.5 Hz) and the integration ratio is 1:1.

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9 6,15 H Relative abundance 100- --09 --09 40- 20- 0.0+ 0.0 142 132 20 26 (13%) $14 120 5100% fully 40 52 (100%) m/z 60 (11%) 62 (4%) 60 09 to Chanical shift ppm) 80 87 (92%) 00 (30%) 100 9 # Chemical shit (ppm) % Transmittance 100 80- 60- 40- 20 132 0 4000 3500 3000 2500 2000 170 111 114 3198 II m 3039 2234 3127 1606 1500 Wavenumbers (cm-¹) 1000 Chemical shift p 500 20 SDBS, National Institute of Advanced Industrial Science and Technology 9 6,15 H Relative abundance 100- --09 --09 40- 20- 0.0+ 0.0 142 132 20 26 (13%) $14 120 5100% fully 40 52 (100%) m/z 60 (11%) 62 (4%) 60 09 to Chanical shift ppm) 80 87 (92%) 00 (30%) 100 9 # Chemical shit (ppm) % Transmittance 100 80- 60- 40- 20 132 0 4000 3500 3000 2500 2000 170 111 114 3198 II m 3039 2234 3127 1606 1500 Wavenumbers (cm-¹) 1000 Chemical shift p 500 20 SDBS, National Institute of Advanced Industrial Science and Technology

Answer rating: 100% (QA)

Here from the mass spectrum the peak at 87 and an M2 peak at 89 which is 1... View the full answer