The first step in the reaction of Alka-Sellzer with stomach acid consists of one mole of sodium
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Question:
The first step in the reaction of Alka-Sellzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO 3 ) reacting with one mole of hydrochloric acid (HCI) to produce one mole of carbonic acid (H 2 CO 3 ), and one mole of sodium chloride (NaCI).
Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 5 mol of NaHCO 3 and 8 mol of HCI.
Which of the two reactants limits the number of moles of H 2 CO 3 that can be made?
- HCI
- NaHCO 3
How much excess reactant remains after the reaction?
Related Book For
Organic Chemistry
ISBN: 978-1118133576
11th edition
Authors: Graham Solomons, Craig Fryhle, Scott Snyder
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