Question: This is the C Code for Karatsuba multiplication. Could you explain this line by line? C Code: #include #include int max(int num1, int num2) {

This is the C Code for Karatsuba multiplication. Could you explain this line by line?

C Code:

#include

#include

int max(int num1, int num2)

{

return (num1 > num2 ) ? num1 : num2;

}

int digits(int x)

{

int count = 0;

while (x != 0)

{

x /= 10;

++count;

}

return count;

}

long int karatsuba(int x,int y)

{

int n,a,b,c,d,i1,i2,half;

long int ac,bd,ad_plus_bc,fin;

if(x

{

return x*y;

}

else

{

n = max(digits(x),digits(y));

half = floor(n / 2) ;

i1 = (pow(10,half));

i2 = (pow(10,(2*half)));

a = floor(x / i1);

b = (x % i1);

c = floor(y / i1);

d = (y % i1);

ac = karatsuba(a,c);

bd = karatsuba(b,d);

ad_plus_bc = karatsuba(a+b,c+d)-ac-bd;

fin = ac * i2 + (ad_plus_bc * i1) + bd;

return fin;

}

}

int main()

{

int x,y;

long int i;

printf(\\\"Enter the Multiplicand : \\\");

scanf(\\\"%d\\\",&x);

printf(\\\"Enter the Multiplier : \\\");

scanf(\\\"%d\\\",&y);

i = karatsuba(x,y);

printf(\\\"Product is %ld \\\",i);

return 0;

}

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