Question: (C++ code) int main() { int num1 = 2; int num2 = 5; int num3; if (num1 > 0 && num2 > 0) num3 =

(C++ code)

int main() { int num1 = 2; int num2 = 5; int num3;

if (num1 > 0 && num2 > 0) num3 = num1 + num2; else if (num1 > num2) num3 = 0;

return 0; }

Disassembly code

int num1 = 2; 00007FF60B70176B mov dword ptr [num1],2 int num2 = 5; 00007FF60B701772 mov dword ptr [num2],5 int num3;

if (num1 > 0 && num2 > 0) 00007FF60B701779 cmp dword ptr [num1],0 00007FF60B70177D jle main+44h (07FF60B701794h) 00007FF60B70177F cmp dword ptr [num2],0 00007FF60B701783 jle main+44h (07FF60B701794h) num3 = num1 + num2; 00007FF60B701785 mov eax,dword ptr [num2] 00007FF60B701788 mov ecx,dword ptr [num1] 00007FF60B70178B add ecx,eax 00007FF60B70178D mov eax,ecx 00007FF60B70178F mov dword ptr [num3],eax 00007FF60B701792 jmp main+53h (07FF60B7017A3h) else if (num1 > num2) 00007FF60B701794 mov eax,dword ptr [num2] 00007FF60B701797 cmp dword ptr [num1],eax 00007FF60B70179A jle main+53h (07FF60B7017A3h) num3 = 0; 00007FF60B70179C mov dword ptr [num3],0

return 0; 00007FF60B7017A3 xor eax,eax } 00007FF60B7017A5 lea rsp,[rbp+128h] 00007FF60B7017AC pop rdi 00007FF60B7017AD pop rbp 00007FF60B7017AE ret

Answer the following 2 questions (1pt each): a. Is the logic (or branching decision) of the if statement in assembly, including the nested if part, as efficient as it could be? If yes, explain why by typing your short explanation in the textbox. If no, "fix" the compiler's assembly code by copying in the inefficient part, and then type in how you would write the assembly code.

b. Is the rest of the code (not counting the if statement) as efficient as it could be? If yes, explain why by typing your short explanation in the textbox. If no, "fix" the compiler's assembly code by copying in the inefficient part, and then type in how you would write the assembly code.

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