$"000"$ is a string commonly found in weak passwords. Remove all occurrences of $"000"$ from codeWord. Then, assign lengthStr

with the length of codeWord.

Ex: If the input is $000n$$$kh!**Z6N$#$g8p,$ then the output is:

Remaining string: $n$$$kh!**Z6N$#$g8p$

Length: $13$

Note:

string.find$($item$)$ returns the index of the first occurrence of item in string. If no occurrence is found, then the function

returns string::npos.

string.replace$($indx$,$ num, subStr$)$ replaces characters at indices indx to indx$+$num$-1$ with a copy of subStr.

int main$()\{$

string codeWord;

int strIndex;

int lengthStr;

cin $>>$ codeWord;

strIndex $=0$;

lengthStr $=0$;

$/*$ Your code goes here $*/$

cout $$ "Remaining string: $"$ codeWord $$ endl;

cout $$ "Length: $"$ lengthStr $$ endl;

return $0$ ;