C PLEASE 000 is a string commonly found in weak passwords Remove all occurrences of 000 from secretStr Then, assign lengthStr with the length of secretStr Ex If the input is 000k G5Pl VJh4 $000, then the output is Remaining string k G5Pl VJh4 $ Length 13 Note string find(item) returns the index of the first occurrence of item in string If no occurrence is found, then the function returns string npos string replace(indx, num, subStr) replaces characters at indices indx to indx num 1 with a copy of subStr D00 is a string commonly found in weak passwords Remove all occurrences of 000 from secretStr Then, assign lengthStr wi he length of secretstr x If the input is 000k G5Pl VJh4 $000, then the output is temaining string k G5P 1 VJh4 $ ength 13 Jote string find(item) returns the index of the first occurrence of item in string If no occurrence is found, then the function returns string npos string replace(indx, num, subStr) replaces characters at indices indx to indx num 1 with a copy of subStr

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Question: C++ PLEASE 000 is a string commonly found in weak passwords. Remove all occurrences of 000 from secretStr. Then, assign lengthStr with the length of

C++ PLEASE

"000" is a string commonly found in weak passwords. Remove all occurrences of "000" from secretStr. Then, assign lengthStr with the length of secretStr. Ex: If the input is 000k!G5Pl>VJh4&$000, then the output is: Remaining string: k!G5Pl>VJh4&$ Length: 13

Note:

- string.find(item) returns the index of the first occurrence of item in string. If no occurrence is found, then the function returns string::npos.

- string.replace(indx, num, subStr) replaces characters at indices indx to indx+num-1 with a copy of subStr.

C++ PLEASE "000" is a string commonly found in weak passwords. Remove

D00" is a string commonly found in weak passwords. Remove all occurrences of "000" from secretStr. Then, assign lengthStr wi he length of secretstr. x : If the input is 000k!G5Pl>VJh4&$000, then the output is: temaining string: k ! G5P 1>VJh4&$ ength: 13 Jote: - string.find(item) returns the index of the first occurrence of item in string. If no occurrence is found, then the function returns string::npos. - string.replace(indx, num, subStr) replaces characters at indices indx to indx+num-1 with a copy of subStr

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