Question: 0 0 Sol ca Solve Problems 35-74 using augmented matrix methods. 55. * - 212 = 1 56. * + 3x2 = 1 201 -

 0 0 Sol ca Solve Problems 35-74 using augmented matrix methods.

0 0 Sol ca Solve Problems 35-74 using augmented matrix methods. 55. * - 212 = 1 56. * + 3x2 = 1 201 - 12=5 3.x] - 212 = 14 57. X1 - 4.19 =-2 58. x1 - 3.X2 = -5 -2x + 12 =-3 -31 - 12 = 59. 3x1 - 12 = 2 60. 2x + 12 = * + 212 = 10 *1 - 20 = -5 61. *+ 2x2 62. 2x1 - 3x2 = -2 2x + 41 =-8 -4x1 + 6.12 = 84. 63. 20 + 12 = 64. 3x1 - 12 =-5 *1 - X2 = -3 * + 3x7 = 5 65. 3x1 - 6.x2 = -9 66. 2x1 - 4x2 = -2 -2xi + 4x7 = - 3x + 612 = 67. 4x] - 2x2 = 68. -6.x] + 2x2 -6x + 3x2 = -3 3x1 - *2 =-2 69. 2x + 12 = 1 70. 2x1 - 12 =-8 rim 4x] - 12=-7 2xj + 12 = 71. 4x1 - 6.12 = 72. 2x1 - 412 = -4 -6x1 + 9x2 = -10 -3x1 + 6.12 = 4.3 Gauss-Jordan Elimination " Reduced Matrices " Solving Systems by Gauss-Jordan Now that you have had some Elimination matrices, we consider systems " Application a system to have the same nu two linear er

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