Question: [ 0 / 1 Points ] SCALCET 9 1 5 . 3 . 0 1 0 . MI . Evaluate the given integral by changing

[0/1 Points] SCALCET915.3.010.MI.
Evaluate the given integral by changing to polar coordinates.
R(4x-y)dA, where R is the region in the first quadrant enclosed by the circle x2y2=16 and the lines x=0 and y=x
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[ 0 / 1 Points ] SCALCET 9 1 5 . 3 . 0 1 0 . MI .

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