Question: 0 1 ( x 2 + x m + 1 ) k ( 4 x + 2 m x m - 1 ) d x

01(x2+xm+1)k(4x+2mxm-1)dx where m=62, and k=5 is given by
0 1 ( x 2 + x m + 1 ) k ( 4 x + 2 m x m - 1 ) d x

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