Question: 0.35 0.30 mt + b 0.20 m =0.102 + 0.0010 0.15 b =-D.348 2 0.0023 = 1.0DO 0.10 0.03 Position IT! 5.50 -0.05 0.10 0.17


0.35 0.30 mt + b 0.20 m =0.102 + 0.0010 0.15 b =-D.348 2 0.0023 = 1.0DO 0.10 0.03 Position IT! 5.50 -0.05 0.10 0.17 0.20 -0.25 x2 x1 -9.30 Run $ 1 I -9.15 D.D 1.0 1.5 2.0 2.5 3.0 3.5 4.0 Time Is! Figure 3: Measuring the velocity V using the slope of x (t) . To measure the velocities and then calculate the momenta, we need determine the slope of the x(t) graph for each cart right before and right after the collision. For example, in Fig. 3 the velocity of the blue cart after the collision is measured by fitting part of the data to a straight line. The slope is equal to the velocity (in this example 0.182 m/s). QUESTION 6: After the collision, is the blue cart moving at a constant velocity, is it speeding up, or is it slowing down? Explain how you can tell this from Figure 3. [ ] constant velocity [ ] speeding up [ ] slowing down
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