$11.$Add a trendline to the graph and use its slope to find Coulomb's constant k$.($Hint: We still have y$=$FE$,$ but now x$=$q$1.$ So the correspondence between the slope variable $,$ and the physics variable is different. Fun fact $-$ the slope not happens to match what we will soon define as the Electric Field.

Slope is y$=1$E$+07(10000000)$ Equation I got is mr$^2/$q$^2=$k$.$

$12.$ Calculate the percent error in k $($where k known is $8\mathrm{.}99$ x $10^9$ Nm$62/$C$^2).$ Also, is the percent error value what you would expect in this case? Why or why not?