1 = 1 - e (R/D)t, -1 = - It and L Let's apply i = (E/R)(1 - e (R/L)t) to a specific R-L circuit. In 10.0 H = 0.050 s 200 0 (Figure 1), suppose & = 120 V, R = 200 $2, and L = 10.0 H. Find (a) the final current after the switch has been closed a long time, (b) Note that this value of T is equal to the definition of the time constant T. the initial time rate of change of the current, immediately after the switch has been closed, and (c) the time at which the current has REFLECT The final current is independent of the inductance because the current is no longer changing with time and there is no induced emf in the reached 63.2% of its final value. s independent of the resistance because the initial current is zero and there is no voltage drop across the resistor. The time constant is directly prop The greater the inductance, the more slowly the current increases. Part A - Practice Problem: Suppose we now want the final current to be 0.293 A , with & and 7 keeping the same values. What value of R should be used? Express your answer in ohms. IVO AEd 0 ] ? R = 600 Submit Previous Answers Request Answer X. Incorrect; Try Again; 9 attempts remaining Figure