$1\mathrm{.}1$ The minimum speed for an ice cube of mass $m$ to stay in contact with the top of the inside of an inverted frictionless hemispherical bowl of radius $R$ is $(gR{)}^{\frac{1}{2}}.$ If the speed of the ice cube at the top is instead twice the minimum, then the normal force on the ice cube will be equal to:

A$)3$ mg

B$)4$ mg

C$)5$ mg

D$)(2^{\frac{1}{2}})mg$

E$)0$ mg