Question: 1 1 Why does det ( P 1 P 2 ) = ( d e t P 1 ) times ( d e t P

11 Why does det(P1P2)=(detP1) times (detP2) for permutations? If P1 needs 2 row exchanges and P2 needs 3 row exchanges to reach I, why does P1P2 reach I from 2+3 exchanges? Then their determinants will be (-1)5=(-1)2(-1)3.
1 1 Why does det ( P 1 P 2 ) = ( d e t P 1 )

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