$1205.$ A rectangular channel with a width of $11m$ carries a flow of $1\mathrm{.}2\frac{m^3}{s}.$ The

water depth in the channel upstream of the hydraulic jump is $0\mathrm{.}3m.$

a$)$ Write an equation that describes the momentum conditions across the

hydraulic jump.

b$)$ Using the momentum expression from a$),$ calculate the fluid velocity on

the downstream side of the hydraulic jump.