Question: 1 . 2 5 J 1 - 0 . 0 4 7 5 J 2 - 0 . 2 0 2 5 J 3 =

1.25J1-0.0475J2-0.2025J3=16226.48
-0.3166J1+1.666T2-0.635J3=1099.47
-0.0675J1-0.3176J2+0.3831J3=0
] can someone help show and explain how these simultaneosu equations are solved to obtain J thank you
1 . 2 5 J 1 - 0 . 0 4 7 5 J 2 - 0 . 2 0 2 5 J 3 =

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