$1-37.$ The tank containing gasoline has a long crack on its side that has an average opening of $10m.$ If the velocity profile through the crack is approximated by the equation $u=10({10}^9)[10({10}^{-6})y-y^2]\frac{m}{s},$ where $y$ is in meters, plot both the velocity profile and the shear stress distribution for the gasoline as it flows through the crack. Take ${}_g=0\mathrm{.}317({10}^{-3})N*\frac{s}{m^2}.$